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學習快評丨qibao666888　　彩??(cai)票??(piao)是??(shi)一?(yi)種??(zhong)概??(gai)率??(lv)游??(you)戲??(xi)??，以?(yi)雙??(shuang)色??(se)球??(qiu)為??(wei)例?(li)??，按??(an)照??(zhao)游??(you)戲??(xi)規(guī)??(gui)則??(ze)??，從??(cong)1-33個??(ge)紅??(hong)色??(se)球?(qiu)號?(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)6個??(ge)、從?(cong)1-16個?(ge)藍?(lan)色??(se)球??(qiu)號??(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)1個??(ge)組??(zu)成??(cheng)1注??(zhu)號??(hao)碼??(ma)??。??而?(er)這??(zhe)樣??(yang)的??(de)組?(zu)合??(he)數(shù)??(shu)有??(you)1772萬??(wan)多??(duo)種??(zhong)??，每??(mei)一??(yi)種??(zhong)組?(zu)合??(he)有??(you)著??(zhe)相??(xiang)同??(tong)的??(de)中??(zhong)獎??(jiang)概??(gai)率??(lv)??。并?(bing)且??(qie)??，每??(mei)次??(ci)開??(kai)獎??(jiang)都??(dou)是?(shi)一??(yi)次??(ci)獨?(du)立??(li)的??(de)隨??(sui)機??(ji)事??(shi)件??(jian)??，毫??(hao)無??(wu)規(guī)??(gui)律??(lv)可??(ke)言??(yan)???！　I進??(jin)行??(xing)預??(yu)測??(ce)的??(de)邏??(luo)輯??(ji)基??(ji)礎??(chu)是??(shi)統(tǒng)??(tong)計??(ji)學??(xue)、機?(ji)器??(qi)學??(xue)習??(xi)和??(he)數(shù)??(shu)據(jù)??(ju)挖?(wa)掘??(jue)??，通??(tong)過??(guo)分??(fen)析??(xi)歷??(li)史??(shi)數(shù)??(shu)據(jù)?(ju)中??(zhong)的??(de)模??(mo)式?(shi)和??(he)規(guī)??(gui)律??(lv)??，推??(tui)斷??(duan)未??(wei)來??(lai)事??(shi)件??(jian)或??(huo)結??(jie)果??(guo)的??(de)可??(ke)能??(neng)性??(xing)??。??但??(dan)是??(shi)??，彩??(cai)票??(piao)每?(mei)次??(ci)開??(kai)獎??(jiang)具??(ju)有??(you)隨??(sui)機??(ji)性??(xing)和??(he)獨??(du)立??(li)性??(xing)??，往??(wang)期??(qi)開??(kai)獎??(jiang)數(shù)??(shu)據(jù)??(ju)與??(yu)未??(wei)來??(lai)開??(kai)獎??(jiang)結??(jie)果??(guo)之??(zhi)間??(jian)沒??(mei)有秘(you)關??(guan)系??(xi)??，即??(ji)使??(shi)AI能??(neng)對?(dui)歷?(li)史??(shi)開??(kai)獎??(jiang)號??(hao)碼?(ma)進??(jin)行??(xing)所??(suo)謂?(wei)的??(de)“復??(fu)雜??(za)”分??(fen)析??(xi)??，也??(ye)無??(wu)法?(fa)預??(yu)測??(ce)下??(xia)一??(yi)次??(ci)開??(kai)獎??(jiang)號??(hao)碼??(ma)??，因??(yin)為??(wei)彩??(cai)票??(piao)的??(de)每??(mei)次??(ci)開??(kai)獎??(jiang)都?(dou)是??(shi)獨??(du)立??(li)事?(shi)件??(jian)??，不??(bu)受??(shou)之??(zhi)前??(qian)結??(jie)果??(guo)的??(de)影??(ying)響??(xiang)??。那??(na)些??(xie)聲??(sheng)稱??(cheng)用??(yong)AI能??(neng)預??(yu)測??(ce)中??(zhong)獎??(jiang)號??(hao)碼??(ma)的??(de)不??(bu)法??(fa)分??(fen)子??(zi)??，只??(zhi)不??(bu)過??(guo)是??(shi)利??(li)用??(yong)了??(le)人??(ren)們?(men)渴??(ke)望??(wang)中??(zhong)獎??(jiang)的??(de)心??(xin)理??(li)??，編??(bian)造??(zao)了??(le)一?(yi)個??(ge)看??(kan)似??(si)“科??(ke)學?(xue)”的??(de)騙??(pian)局??(ju)??。。