2025-03-26 00:33:44 來源:新華網(wǎng)
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學習快評丨qibao666888 據(jù)??(ju)測??(ce)算??(suan)??,目??(mu)前??(qian)我??(wo)國??(guo)林??(lin)草??(cao)年??(nian)碳??(tan)匯??(hui)量??(liang)超??(chao)過??(guo)12億??(yi)噸?(dun)二??(er)氧??(yang)化??(hua)碳??(tan)當??(dang)量??(liang)??,居??(ju)世??(shi)界??(jie)首??(shou)位??(wei)??,是??(shi)實??(shi)現(xiàn)??(xian)碳??(tan)中??(zhong)和??(he)目??(mu)標??(biao)的??(de)“壓??(ya)艙??(cang)石??(shi)”??,在??(zai)減??(jian)緩??(huan)全??(quan)球??(qiu)氣??(qi)候??(hou)變??(bian)化??(hua)方?(fang)面??(mian)發(fā)??(fa)揮??(hui)著??(zhe)不??(bu)可??(ke)替??(ti)代?(dai)的??(de)作??(zuo)用??(yong)?。??鞏??(gong)固??(gu)和??(he)提??(ti)升??(sheng)林??(lin)草??(cao)生?(sheng)態(tài)??(tai)系?(xi)統(tǒng)?(tong)碳??(tan)匯??(hui)能??(neng)力??(li)??,要??(yao)擴??(kuo)大??(da)林??(lin)草??(cao)面?(mian)積??(ji)??,增??(zeng)加?(jia)林??(lin)草??(cao)碳??(tan)庫??(ku)總??(zong)量??(liang)??,提??(ti)高??(gao)林??(lin)草?(cao)資??(zi)源??(yuan)質??(zhi)量??(liang)??,提??(ti)升??(sheng)碳??(tan)匯??(hui)增??(zeng)量??(liang)??,加??(jia)強??(qiang)林??(lin)草??(cao)資??(zi)源??(yuan)保??(bao)護??(hu)??,減??(jian)少?(shao)碳??(tan)庫??(ku)損??(sun)失??(shi)?。此??(ci)外??(wai)??,還??(hai)要??(yao)創(chuàng)??(chuang)新??(xin)林??(lin)業(yè)??(ye)碳??(tan)匯??(hui)應??(ying)用??(yong)場??(chang)景??(jing)??,探??(tan)索??(suo)多??(duo)種??(zhong)鞏??(gong)固??(gu)提?(ti)升??(sheng)碳?(tan)匯??(hui)能??(neng)力??(li)途?(tu)徑??(jing)與??(yu)價??(jia)值??(zhi)實??(shi)現(xiàn)??(xian)模??(mo)式??(shi)??! 〗??(jin)年??(nian)的??(de)《政??(zheng)府??(fu)工??(gong)作?(zuo)報??(bao)告??(gao)》提??(ti)出??(chu)??,“統(tǒng)??(tong)籌??(chou)推??(tui)進??(jin)山??(shan)水??(shui)林??(lin)田??(tian)湖??(hu)草??(cao)沙??(sha)一??(yi)體??(ti)化??(hua)保??(bao)護??(hu)和??(he)系??(xi)統(tǒng)??(tong)治??(zhi)理?(li)”“推??(tui)動??(dong)‘三?(san)北??(bei)’工??(gong)程??(cheng)標??(biao)志?(zhi)性??(xing)戰(zhàn)??(zhan)役??(yi)取??(qu)得??(de)重??(zhong)要??(yao)成??(cheng)果??(guo)”?。??這??(zhe)意??(yi)味??(wei)著??(zhe)我?(wo)們??(men)仍??(reng)需??(xu)厚??(hou)植??(zhi)林??(lin)草??(cao)資??(zi)源??(yuan)??,持?(chi)續(xù)??(xu)推??(tui)動??(dong)國??(guo)土??(tu)綠??(lv)化??(hua)??,久??(jiu)久??(jiu)為??(wei)功??(gong)、善??(shan)作??(zuo)善??(shan)成??(cheng)?。。