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　　AI進??(jin)行??(xing)預??(yu)測?(ce)的??(de)邏?(luo)輯??(ji)基??(ji)礎??(chu)是??(shi)統(tǒng)?(tong)計??(ji)學?(xue)、機??(ji)器??(qi)學??(xue)習??(xi)和??(he)數(shù)??(shu)據(jù)??(ju)挖??(wa)掘??(jue)??，通??(tong)過??(guo)分??(fen)析?(xi)歷??(li)史??(shi)數(shù)??(shu)據(jù)?(ju)中??(zhong)的??(de)模??(mo)式??(shi)和?(he)規(guī)??(gui)律??(lv)??，推??(tui)斷??(duan)未??(wei)來??(lai)事??(shi)件??(jian)或?(huo)結??(jie)果??(guo)的??(de)可??(ke)能??(neng)性??(xing)??。??但??(dan)是??(shi)??，彩??(cai)票??(piao)每??(mei)次??(ci)開??(kai)獎??(jiang)具??(ju)有??(you)隨??(sui)機??(ji)性?(xing)和??(he)獨??(du)立??(li)性??(xing)??，往??(wang)期?(qi)開?(kai)獎??(jiang)數(shù)??(shu)據(jù)??(ju)與??(yu)未??(wei)來??(lai)開??(kai)獎??(jiang)結??(jie)果?(guo)之??(zhi)間??(jian)沒??(mei)有?(you)關??(guan)系??(xi)??，即??(ji)使??(shi)AI能??(neng)對??(dui)歷??(li)史??(shi)開??(kai)獎?(jiang)號??(hao)碼??(ma)進??(jin)行?(xing)所??(suo)謂??(wei)的??(de)“復??(fu)雜??(za)”分??(fen)析??(xi)??，也??(ye)無??(wu)法??(fa)預??(yu)測?(ce)下??(xia)一??(yi)次??(ci)開?(kai)獎??(jiang)號??(hao)碼??(ma)??，因??(yin)為??(wei)彩??(cai)票??(piao)的?(de)每??(mei)次??(ci)開??(kai)獎??(jiang)都??(dou)是?(shi)獨??(du)立??(li)事??(shi)件??(jian)??，不??(bu)受??(shou)之??(zhi)前??(qian)結??(jie)果??(guo)的??(de)影??(ying)響??(xiang)??。那??(na)些??(xie)聲??(sheng)稱??(cheng)用??(yong)AI能??(neng)預??(yu)測??(ce)中??(zhong)獎??(jiang)號??(hao)碼??(ma)的?(de)不??(bu)法??(fa)分??(fen)子??(zi)??，只??(zhi)不??(bu)過??(guo)是??(shi)利??(li)用??(yong)了??(le)人??(ren)們??(men)渴??(ke)望??(wang)中??(zhong)獎??(jiang)的??(de)心??(xin)理??(li)??，編??(bian)造??(zao)了??(le)一?(yi)個??(ge)看??(kan)似??(si)“科??(ke)學??(xue)”的??(de)騙??(pian)局??(ju)??。。